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3 years ago

Pls help me, first right-brainliest:)))))

Mathematics

2 answers:

saul85 [17]3 years ago

4 0

D I don’t need brainlets

Vladimir [108]3 years ago

3 0

The answer is d! For your question.

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0=x^2-4x+3 how many roots does this equation have

mars1129 [50]

Answer:

No complex roots; 3 real roots

Step-by-step explanation:

If a third order polynomial has any complex roots, then as a rule it has 1 real root and 2 complex roots. In this particular case, the polynomial has three real roots, as can be determined by graphing the function. The graph crosses the x-axis in 3 places.

5 0

3 years ago

I need help with math 1010<br>completing the square<br>x^2-9x=10

Citrus2011 [14]

$x^2-9x=10|+20.25\\
x^2-9x+20.25=30.25\\
(x-4.5)^2=30.25\\
x-4.5=5.5 \vee x-4.5=-5.5\\
x=10 \vee x=-1$

7 0

3 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

3 years ago

The grocery store has 2 1/3 times as many cashiers in late afternoon than in the morning. If there are 21 cashiers at 10:00 am,

Fantom [35]

Well 21 times 2 is 42 and 1/3 of 21 is 7 so 42+7 is 49. hope this is right

7 0

2 years ago

una pizzeria hace pizzas de varios tamaños y las vende en cajas hexagonales de 39 cm de lado y 4.7 cm de alto ¿que cantidad de c

Makovka662 [10]

Area de la base es un hexagono: Nota: asumiendo que 39 cm son el lado de un hexagono. Menuda pizza.

A = 3*sqrt(3)/2*a^2 = 3*sqrt(3)/2*39^2 = 3951.67391746839972 cm^2

Hay dos base y tapa, doble:

7903.34783493679944 cm^2

Luego los lados verticales:

6 * 39 * 4.7 = 1099.8 cm^2

TOtal = 9003.14783 = 9003.147 cm^2 = 9003.15 cm^2

3 0

3 years ago