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Paraphin [41]
2 years ago
5

What is the recursive of this:

Mathematics
1 answer:
abruzzese [7]2 years ago
3 0

Answer:

a_n=a_{n-1}+2^{n-1}\ \ n>1

Step-by-step explanation:

Recursive Sequence

We are given the following sequence:

-1, 1, 5, 13...

It's required to find the recursive term for the sequence.

A recursive formula calculates each term as a function of one or more previous terms.

To find the recursive formula, we must find a pattern and transform it into a math expression.

Let's write the sequence, and below it, the difference of consecutive terms:

-1,   1,   5,   13...

+2,  +4,  +8

Note the difference between consecutive terms is always a power of 2, starting from 2^1, 2^2, 2^3.

The exponent is one less than the number of the term, thus:

a_n-a_{n-1}=2^{n-1}

Thus:

\mathbf{a_n=a_{n-1}+2^{n-1}\ \ n>1}

Testing:

n=1

a_1=-1 (given).

n=2

a_2=a_{1}+2^{2-1}=-1+2^{1}=1

n=3

a_3=a_{2}+2^{3-1}=1+2^{2}=5

n=4

a_4=a_{3}+2^{4-1}=5+2^{3}=13

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Dafna11 [192]

Answer:

a + b \geq 30

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Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

b - a \geq 10

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

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3 years ago
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Answer:

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Rearrange to make x the subject of 4(x-3)/a=y
IrinaVladis [17]

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Step-by-step explanation:

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I hope this helps.

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Answer:

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Answer:

\boxed{\sf (f-g)(x) = -{x}^{2}  + 3x + 7}

Given:

\sf f(x) = 3x + 1 \\ \sf g(x) =  {x}^{2}  - 6

To find:

\sf (f - g)(x) = f(x) - g(x)

Step-by-step explanation:

\sf \implies(f - g)x = f(x) - g(x) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1) - ( {x}^{2}  - 6) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1)  + (-  {x}^{2}  + 6) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 3x + 1 -  {x}^{2}  + 6 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = - {x}^{2}  + 3x + 1 + 6 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    =  -{x}^{2}  + 3x + 7

8 0
3 years ago
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