Please provide the formula for me to answer
The expected values of the binomial distribution are given as follows:
1. 214.
2. 21.
3. 31.
<h3>What is the binomial probability distribution?</h3>
It is the <u>probability of exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
For item 1, the parameters are:
p = 3/7, n = 500.
Hence the expected value is:
E(X) = np = 500 x 3/7 = 1500/7 = 214.
For item 2, the parameters are:
p = 0.083, n = 250.
Hence the expected value is:
E(X) = np = 250 x 0.083 = 21.
For item 3, the parameters are:
p = 1/13, n = 400.
Hence the expected value is:
E(X) = np = 400 x 1/13 = 31.
More can be learned about the binomial distribution at brainly.com/question/24863377
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The answer for the graph would be C. While x is less than or equal to 0, there is the graph of -4x. While x is greater than x, there is the graph of -5 (horizontal line). Furthermore, the closed dot at the end of the -4x represents the less than or EQUAL TO. The dot at the end of the -5 is open because it is only true when x > 0.
The range (y-values where the graph exists) is [-5]∪[0, infinity)
Answer:
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Step-by-step explanation:
The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.
We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.
T interval:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(
). So we have T = 1.761
The margin of error is:
M = T*s = 1.761*5 = 8.805.
The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
