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storchak [24]
3 years ago
10

Please help me with this question, thank you so much!!!!!

Mathematics
1 answer:
Scilla [17]3 years ago
3 0

Answer:

275 to break even for those 3 months.

100 to break even just for march

break even means no profit or equal sales + expenses

Step-by-step explanation:

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A desert has both fruit and yoghurt inside.Altogether the mass of the fruit and yoghurt is 175g. The ratio of the mass of fruit
Dafna11 [192]

Answer:

125g

Step-by-step explanation:

You can find the mass of the yoghurt by dividing the mass of the fruit and the yoghurt by the sum of the ratio,(2+5), then multiplying that value by 5.

8 0
3 years ago
A machine can produce 6 yards of fabric in 2 minutes. If it works at the same rate, how much fabric can the machine produce in 1
olga55 [171]

Answer:

im not sure but i think is 1

4

8 0
2 years ago
Read 2 more answers
belinda is digging a round flower garden in her backyard. she has 19 feet of rubber edging to place around the garden. what is t
Maurinko [17]
"Around the garden"= circumference

Find diameter from circumference formula

Circumference= πd
19= (3.14)d
divide both sides by 3.14
6.04788= d

Find radius
d÷2= 3.0239

Insert r= 3.0239 into Area formula

Area= πr^2
A= π(3.0239)^2
A= (3.14)(3.0239)^2
A= 28.71 square feet

ANSWER: 28.71 square feet is the area of the new garden

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
3. Write an equation of the line that passes through (-2, 8) and (4,4).
gtnhenbr [62]

y =  -  \frac{2}{3} x +  \frac{20}{3}

Step-by-step explanation:

y=mx+c

label your points

(-2;8). pnt2

(4;4). pnt1

m =  \frac{y2 - y1}{x2 - x1}

m =  \frac{8 - 4}{ - 2 - 4}

m =  \frac{  4}{ - 6}

m = -   \frac{2}{3}

substitute gradient and 1 point into equation to get c

8 = ( -  \frac{2}{3} )( - 2) + c

8 =  \frac{4}{3}  + c

c = 8 -  \frac{4}{3}

c =  \frac{20}{3}

Therefore the equation is

y =  -  \frac{2}{3} x +  \frac{20}{3}

4 0
2 years ago
Is <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D" id="TexFormula1" title="\frac{x^{2}}{2}" alt="\frac{x^{2}}
Xelga [282]
1/2 x^2
hope this helped you
8 0
2 years ago
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