The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how
would you calculate in terms of Pi how much longer the outer edge is than the inner edge?
1 answer:
Answer:
4.4mm
Step-by-step explanation:
Circumference of circle
2 Pi r
Diameter of coin = 22mm
Therefore the radius = 11mm
Therfroe the outer edge (circumference)
= 2 Pi r
= 2 x Pi x 11
=69.11mm
For the inner edge
Diameter = 5
Radius = 2.5
Therefroe inner edge (circumference)
= 2 Pi r
= 2 x Pi x 2.5
= 15.7mm
The difference is
69.11 - 15.7
=4.4mm
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