we conclude that the solution for the given algebraic expressions are:
- J = -5
- s = -106
- t = 38
- r = -60
- a = 57
<h3>
How to solve these algebraic expressions?</h3>
Here we have some simple algebraic expressions:
The first one is:
-25/J = 5
We want to solve this for J.
Remember that we can perform the same operation in both sides of the equation, then we cans tart by multiplying both sides by J.
(-25/J)*J = 5*J
-25 = 5*J
Now we can divide both sides by 5, so we isolate J:
(-25)/5 = (5*J)/5
-5 = J
We conclude that the solution is J = -5.
Now, similarly for the other equations we have that:
16 + s = -90
Here we subtract 16 in both sides:
s = -90 - 16 = -106
13 + t = 51
Here we subtract 13 in both sides:
t = 51 - 13 = 38
r/10 = (-6)
Here we multiply both sides by 10:
r = (-6)*10 = -60
a + (-12) = 45
Here we add 12 in both sides:
a = 45 + 12 = 57
Then we conclude that the solution for the given algebraic expressions are:
- J = -5
- s = -106
- t = 38
- r = -60
- a = 57
If you want to learn more about algebraic expressions:
brainly.com/question/4344214
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Answer:
His interest is $2340 his total is $8840
Step-by-step explanation:
19900 x .03 = 597
597 x 10 = 5970
5970 + 19900 = 25870
The line contains (9,y) and (-6,3) Then y is 13
<em><u>Solution:</u></em>
Given that a line contains (9, y) and (-6, 3)
Slope of line is 
To find: y
<em><u>The slope of line is given as:</u></em>
<em><u>Substituting the values in formula,</u></em>
Substitute 
2(-6 - 9) = 3(3 - y)
Multiplying the terms with terms inside bracket
-12 - 18 = 9 - 3y
Move the variable to one side
-30 = 9 - 3y
On solving we get,
3y = 30 + 9
3y = 39
Divide both sides by 3, we get
y = 13
Thus y = 13
