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Vikentia [17]
2 years ago
8

Which two numbers doesStartRoot 128 EndRoot lie between on a number line? 11. 0 and 11. 1 11. 2 and 11. 3 11. 3 and 11. 4 11. 4

and 11. 5.
Mathematics
1 answer:
Alex73 [517]2 years ago
7 0

A number line is a representation of a graded straight line. The number √128  will lie between 11.3 and 11.4.

<h3>What is a number line?</h3>

A number line is a representation of a graded straight line that serves as an abstraction for real numbers, which are represented by the letter R. A real number is considered to correspond to every point on a number line, and a point to every real number.

In order to know the location of the √128, we need to write the number  √128 in decimal form, therefore, the value of √128 can be written as,

\sqrt{128} = 11.3137 \approx 11.31

Now, on the number line if we plot √128 we will see that it will lie between 11.3 and 11.4, as shown below.

Hence, the number √128  will lie between 11.3 and 11.4.

Learn more about Number Line:

brainly.com/question/557284

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Rainbow [258]
To draw a histogram, you need two axes. The horizontal axis is the day and the vertical axis is the number of text messages. For the first day, there are 20 text messages. This is represented by a bar starting from the horizontal axis labeled Day 1 going up to the point where the vertical axis indicates 20 text messages. This is done for the rest of the data. Afterwards, a line is drawn from the vertex of the axes connected to the top of the first bar. Then from the top of the first bar, a line connects it to the top of the next bar. This is done for all the bars before producing a histogram.
6 0
3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
Multiply: (-5qr) × (-2pqr) × pq​
ahrayia [7]

Answer:

The product of (-5·q·r) × (-2·p·q·r) × p·q is 10·q³·r²·p²

Step-by-step explanation:

The question relates to the rules of multiplication of variables and indices rules, and simplifification of an expression ;

The given expression is (-5·q·r) × (-2·p·q·r) × p·q

Therefore, we have;

(-5·q·r) × (-2·p·q·r) × p·q = (-5) × (-2) × q×q×q × r×r ×p×p = 10 × q³ × r² × p²

10 × q³ × r² × p² = 10·q³·r²·p²

∴ (-5·q·r) × (-2·p·q·r) × p·q = 10 × q³ × r² × p² = 10·q³·r²·p²

(-5·q·r) × (-2·p·q·r) × p·q = 10·q³·r²·p².

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