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marishachu [46]
4 years ago
13

1. If 2b + 1 =b + 6, then b

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
4 0

Answer:

5

Step-by-step explanation:

b=5

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Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss
mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

\frac{a}{b}+\frac{c}{d}

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{ad+cb}{bd}

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0
3 0
3 years ago
Write (3 − 7i) − (-11 + 5i) as a complex number in standard form.
Katyanochek1 [597]
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Simplify the expression:<br> 6b+7b2+4
Bezzdna [24]

Answer:

13b + 6= 18b

Step-by-step explanation:

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3 years ago
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