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Anika [276]
3 years ago
7

To prepare for a bake-off, Joy used 690 grams of flour each day for 2 weeks. How many kilograms did Joy use in those 2 weeks? 1

g = 0.001 kg
Mathematics
2 answers:
lianna [129]3 years ago
8 0
0.69 kg I think sorry if wrong!!!!
jarptica [38.1K]3 years ago
7 0

Answer:

0.69 kg

Step-by-step explanation:

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4{2a(3a-b)+3ab}+5{3b(a+2b)-4ab}
Paraphin [41]
Follow order of operations.
Distribute what is in the parentheses.
4[6a^2 -2ab +3ab] + 5[3ab + 6b^2 -4ab]

Combine like terms in the brackets.
4[6a^2 + 3ab] + 5[-1ab + 6b^2]

Distribute the 4 and the 5.
24a^2 + 12ab -5ab + 30b^2

Combine like terms.
24a^2 +7ab + 30b^2

That's your final answer:
24a^2 +7ab + 30b^2
5 0
3 years ago
Which is a factor of
Zolol [24]

Answer:

<h2>OOOOOOOOOOOOOO9ONOOOOOOOOOOOO</h2>
7 0
3 years ago
Solve For X <br> A 3 <br> B 30<br> C 60<br> D 90
Anarel [89]

Answer:

sln

10x+10x+30+90=180

20x+120=180

20x=180-120

20x=60

x=3

the answer is A) 3

8 0
3 years ago
Help me anyone please &amp; thank you
viktelen [127]

Answer: i'm pretty sure it's option A

8 0
3 years ago
9. An article was sold at a profit of 12%. Had it been sold for Nu 80 more, there would be a profit of
Kamila [148]

Answer:

<em>The cost price of the article was Nu 1,000</em>

<em>The original selling price was Nu 1,120</em>

<em>The second selling price was Nu 1,200</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = Original selling price of the article

y = Cost of the article

The first condition implies that the difference between the selling price and the cost price (the profit) is 12%. Recall the profit % is always calculated with respect to the cost, that is, the profit at the first condition is:

0.12y = Original profit

Setting up the equation, we have:

x-y=0.12y

The second condition states the selling price is 80 Nu more than before, that is:

x+80= Second selling price of the article

y = Cost of the article (it doesn't change)

The profit of this condition is 20%, thus:

0.2y = Second profit

This produces a second equation:

x+80-y=0.2y

Let's put both equations together to form a system of equations:

x-y=0.12y

x+80-y=0.2y

Operating on both equations:

x=1.12y

x=1.2y-80

Equating both equations, we have an equation with only y's:

1.12y=1.2y-80

Subtracting 1.2y on each side:

1.12y-1.2y=-80

Operating:

-0.08y=-80

Solving:

\displaystyle y=\frac{-80}{-0.08}=1,000

a)

The cost price of the article was Nu 1,000

b) The selling price of the article will be calculated in both cases:

Original selling price: x=1.12y= 1.12*1000=1,120

The original selling price was Nu 1,120

The second selling price was x+80=1,200

The second selling price was Nu 1,200

8 0
4 years ago
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