Answer:
<u>U = mgh = (1250 kg)(9.8 m/s2)(2m) = ? J</u>
HOPE THIS HELPS
Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5
Answer:
x = 6
Step-by-step explanation:
move all terms to the left:
-1.5x+12-(2.5x-12)=0
get rid of parentheses
-1.5x-2.5x+12+12=0
add all the numbers together, and all the variable.
-4x+24=0
move all terms containing x to the left, all other terms to the right
-4x=-24
x=-24/-4 - divide
x=+6
Answer:
The answer to your question is: I bought 7 snacks
Step-by-step explanation:
Data
beginning balance = $42 = b
lunch = $1.80 = l
snack = $ 0.85 = s
final balance = $0.05 = f
f = b - 1.8l - 0.05s
0.05 = 42 - 1.8l - 0.85s
After 20 days I spent = 1.8(20) in lunches = $36
0.05 = 42 - 36 - 0.85s
0.05 = 6 - 0.85s
0.05 - 6 = -0.85s
-5.95 = -0.85s
s = -5.95/-0.85
s = 7
A supplmentary angle = 180°
∠BDE and ∠BDF are vertical angles, and so are congruent.
∠BDF = 125°, because ∠BDF ≅ ∠BDE.
∠CDA ≅ ∠EDF
∠CDA = 90°
<span>line BJ </span> is angle bisector of ∠CDA. ∠CDB is 1/2 of ∠CDA
∠CDA = 90°
∠CDB = 90/2
∠CDB = 45°
∠GDF is a vertical angle of ∠CDB, and it's measurement will be the same as ∠CDB.
∠GDF ≅ ∠CDB
∠CDB = 45°
∠GDF = 45°
∠GDF = 45° should be your answer
hope this helps
