The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
Answer:
Step-by-step explanation:
First one is C+1.25=2.50
2. 5V=30
3. X-44
I hope this helped.
The graph with the highest absolute value is the steepest. In this case, the answer is C.
Answer:
Let's define all the possible forms:
slope-intercept: y = a*x + b
point-slope: y - y1 = a*(x - x1) (where (x1, y1) is a point in the line)
standard form: a*x + b*y = c
then:
a) 7x + 5y = 8
This is in standard form.
b) y − 5 = 3*(x − 9)
This is in point slope form.
c) y = 7x + 9
This is in slope-intercept form.
d) 8x − 9y = −2
This is in standard form.
Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
