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3 years ago

HELPPP can someone answer atleast some of these !!

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

Can someone help me too in my math problems

STALIN [3.7K]3 years ago

7 0

I can help you understand it but I am very busy so I can't write out all of these...

Do you know PEMDAS ita the order in whihc you solve equation and then you combine like terms so the variables and then numbers without variables. and when u multiply or divide negative and positives its negative and two of the same like negative and negative is positive and vice verse... alsoosososos you can download apps on your phone that will literally do the work for u... worse case just guess and ask your teacher if u can have help becasue your super lost they will 99.999% of the time help u and give u time to turn it in for full points after they give u answer lol :D sorry i couldnt give u answer hopefully i helped. becasue im not sure if u simplify or solve or what

You might be interested in

Please help me! Due soon!

givi [52]

Answer:

70/9

Step-by-step explanation:

We have the quadratic:

$3x^2+4x-9$

So, let’s find the roots of the quadratic. We will set the expression equal to 0:

$3x^2+4x-9=0$

Testing for factors, we can see that our quadratic isn’t factorable.

So, we can use the Quadratic Formula. The quadratic formula is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case:

$a=3, b=4,\text{ and } c=-9$

Therefore, by substitution:

$\displaystyle x=\frac{-(4)\pm\sqrt{(4)^2-4(3)(-9)}}{2(3)}$

Evaluate:

$\displaystyle x=\frac{-4\pm\sqrt{124}}{6}$

Simplify the square root:

$\sqrt{124}=\sqrt{4\cdot31}=2\sqrt{31}$

Hence:

$\displaystyle x=\frac{-4\pm2\sqrt{31}}{6}$

Reduce:

$\displaystyle x=\frac{-2\pm\sqrt{31}}{3}$

So, our roots are:

$\displaystyle x_1=\frac{-2+\sqrt{31}}{3}, x_2=\frac{-2-\sqrt{31}}{3}$

We want to find the sum of the <em>squares</em> of our two roots. So, let’s square each term:

$\displaystyle (x_1)^2=\Big(\frac{-2+\sqrt{31}}{3}\Big)^2$

Square. For the numerator, we can use the perfect square trinomial patten where:

$(a+b)^2=(a^2+2ab+b^2)$

Therefore:

$\displaystyle (x_1)^2=\Big(\frac{(-2)^2+2(-2)(\sqrt{31})+(\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_1)^2=\frac{35-4\sqrt{31}}{9}$

Similarly, for the second root, we will have:

$\displaystyle (x_2)^2=\Big(\frac{-2-\sqrt{31}}{3}\Big)^2$

So:

$\displaystyle (x_2)^2=\Big(\frac{(-2)^2+2(-2)(-\sqrt{31})+(-\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_2)^2=\frac{35+4\sqrt{31}}{9}$

Therefore, our sum will be:

$\displaystyle (x_1)^2+(x_2)^2\\\\ \begin{aligned} &=\frac{35-4\sqrt{31}}{9}+\frac{35+4\sqrt{31}}{9}\\&=\frac{35-4\sqrt{31}+35+4\sqrt{31}}{9}\\&=\frac{70}{9}\end{aligned}$

Therefore, our final answer is 70/9.

3 0

3 years ago

Round 78500 to the nearest thousand. Enter your answer in the box below<br> without a comma.

Svetllana [295]

Answer:

79000

Step-by-step explanation:

The 8 is in the thousands place. We look at the hundreds place

5 is in hundreds place. It is 5 or greater so we round up

The 8 becomes a 9

78500 becomes 79000

5 0

4 years ago

Aaron Lloyd what is a?<br>

algol [13]

Answer:

Rugby lawyer

Step-by-step explanation:

Aaron is a partner in the firm’s dispute resolution division. He advises clients on a range of litigious and risk related matters, with particular expertise in the areas of corporate misconduct, white collar criminal and regulatory affairs, sports law and employment law. Aaron leads our sports law practice, and is a member of the firm’s health and safety, public law, and organisational integrity teams.

Well regarded by clients for his ability to analyse and strategise complex situations, Aaron is internationally recognised for his ability to implement pragmatic and commercial strategies to minimise risk and create opportunity. This ability has resulted in clients avoiding significant litigation and commercial consequences.

Aaron is an experienced advocate, having argued cases in the District Court, High Court, Employment Court, the Court of Appeal and Supreme Court of New Zealand, along with numerous tribunals.

He is recognised by international legal directories including by Chambers & Partners (Asia Pacific), Who’s Who Legal, Expert Guides, Best Lawyers and Doyles.

Before joining MinterEllisonRuddWatts Aaron practiced as a barrister with Paul Davison QC, and has lectured at the University of Auckland.

6 0

3 years ago

NEED MAJOR HELP FAST

Softa [21]

It’s 82 broskie dude

5 0

3 years ago

Triangle ABC is congruent to triangle DEF. what reason can be used to show that line AB is congruent to line DE.

ki77a [65]

If triangle ABC is congruent to triangle DEF, then line AB is congruent to line DE by CPCTC (Corresponding Parts of Congruent Triangles are Congruent).

4 0

3 years ago

*HELPPP* can someone answer atleast some of these !!

HELPPP can someone answer atleast some of these !!