The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib

For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer:
1080 in^2
Step-by-step explanation:
The answer is 1,1500 because you ha e to subtract the lowest to highest number
Whatever is inside parentheses first [g(x)], is what you would evaluate first, then after that, you would substitute that answer into the f(x) function for EVERY "X" YOU SEE:
[2x² + 5]² + [2x² + 5] + 2
[2x² + 5]² + [2x² + 7]↓
This is your final answer. You get it?
Answer:
No solution I believe
Step-by-step explanation: