ILL GIVE BRAINLIST I ONLY HAVE 1O MINUTES

2 answers:

6 0

Hi I think you haven’t put your choices it’s will be hard to answer. So if you repost the answer I can probably help you!!

CaHeK987 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

I am sorry that I might not be able help you, just try and sound smart while saying if u change a then the value of a/x would change, thus changing everything because the fraction in which you are using in this situation would be different. And for b be like the difference between the numbers would be different and c the product. Idek if this is what the question is asking. lol

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How to find the area of 2 half circles and a rectangle

gladu [14]

Hello!

We use different formulas to calculate the areas of different shape.

RECTANGLE:

To find the area of a rectangle, we must simply multiply its length by its width. The formula for its area is:

A = l × w

SEMICIRCLE:

Since the formula for a circle is pi × r × r, we must use the same formula but divide it in half, because a semicircle is a half circle, which is why its area would also be half of a circle's. The formula for a semicircle's area is:

A = 1/2 pi × r × r

Tip:

Write these formulas down and memorize them so that you don't forget them. You'll have to use these formulas quite often when finding the area of these shapes.

6 0

4 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$