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2 years ago

14

can someone help me with this? pls explain the steps. You don't have to do them all I just need to know the steps to solve. Much

appreciated

1 answer:

Luba_88 [7]2 years ago

6 0

Answer:

can u help me with my history homework and ill help u with urs

Step-by-step explanation:

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In the diagram, PQ¯¯¯¯¯¯¯¯ is tangent to the circle at point Q, and secant PS¯¯¯¯¯¯¯ intersects the circle at points R and S. Th

dimaraw [331]

The tangent secant theorem says

PR × PS = PQ²

4 × (4+5) = PQ²

36 = PQ²

PQ=6

Answer: 6

3 0

2 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

b.

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

c.

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

2 years ago

Read 2 more answers

I need help ill give brainiest

Gnoma [55]

Answer:

9 ft

Step-by-step explanation:

its volume is equal to the area by height;

(2.5 x 3)h = 67.5

h = 9ft

5 0

2 years ago

Read 2 more answers

What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°

IceJOKER [234]

Answer:

16.75 square cm

Step-by-step explanation:

$Area \: of \: sector = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{30 \degree}{360 \degree} \times 3.14 \times {8}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 64 \\ \\ = \frac{1}{3} \times 3.14 \times 16 \\ \\ = \frac{1}{3} \times 50.24 \\ \\ = 16.7466667 \\ \\Area \: of \: sector = 16.75 \: {cm}^{2}$

3 0

2 years ago

Find ( f - g)(x).<br><br> f (x) = -2x2 - 2x - 3 and g(x) = 3x2 - 4x - 4

Kruka [31]

Answer:

$\large\boxed{(f-g)(x)=-5x^2+2x+1}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\\text{We have}\ f(x)=-2x^2-2x-3\ \text{and}\ g(x)=3x^2-4x-4.\\\\\text{Substitute:}\\\\(f-g)(x)=(-2x^2-2x-3)-(3x^2-4x-4)\\\\(f-g)(x)=-2x^2-2x-3-3x^2+4x+4\qquad\text{combine like terms}\\\\(f-g)(x)=(-2x^2-3x^2)+(-2x+4x)+(-3+4)\\\\(f-g)(x)=-5x^2+2x+1$

3 0

3 years ago