(Credit goes to google)<span>f ( x ) = a </span>x<span>. where x is a variable, and a is a constant called the base of the </span>function<span>. The most commonly encountered </span>exponential-function<span> base is the transcendental number e , which is equal to approximately 2.71828.</span>
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Answer:
11
Step-by-step explanation:
4 × (2 3/4) = 4×2 + 4×(3/4) = 8 + 3 = 11
or
4 × (2 3/4) = 4 × 11/4 = 11
Answer:
Area = (36π - 12πx + x²π) mm²
Step-by-step explanation:
Given that,
radius of lense = 6mm
Length from outer layer of pupil to lense = x mm
Radius of pupil = 6 - x mm
<h3>
Formula to calculate area of pupil</h3><h3>
Area = π r²</h3>
<em> where r is radius of pupil</em>
Area = π (6 -x)²
Area = π (6² -2(6)(x) + x²)
Area = π (36 -12x +x²)
Area = (36π - 12πx + x²π) mm²
So, the polynomial in standard form that represent the area of pupil in terms of π = (36π - 12πx + x²π) mm²
I guess the question is incomplete...
