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alexandr402 [8]
3 years ago
10

ME ajudem porfavor não aguento mais, tá muito dificil

Mathematics
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer:

say it in English plZz

I can't understand Spanish or whatever ur saying sorry

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Which expression is equivalent to x^2-10x+24
Brut [27]

Answer:

(x-4)(x-6)

Step-by-step explanation:

By factorization, x^2-10x+24 can be written in the form (x-4)(x-6). Thus the roots of the quadratic equation are x= 4 and 6 respectively.

4 0
3 years ago
What is the GCF of 96x5 and 64x2? 32x 32x2 32x3 32x5
Lapatulllka [165]
The answer to your question would be 32x^2
6 0
3 years ago
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If you buy 3 shirts, you get 10% discount. If you paid $270 for 6 shirts
earnstyle [38]

Answer:

50$

Step-by-step explanation:

270/6=45

10% of 50 is 5

so 50-5= 45

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3 years ago
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Line a is parallel to line b, m 6=85 and m 3=2x. Find m 1.
FromTheMoon [43]
The sum of the angles <6 and <3 must be 180. Since <3 and <1 are opposed to the top, their measure are equal. We need then to calculate the measure of angle >3 = 180 - <6 = 180-85=95

m(<1) = 95 

8 0
3 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

#SPJ1

4 0
9 months ago
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