This is a classic example of a 45-45-90 triangle: it's a right triangle (one angle of 90) & two other sides of the same length, which means two angles of the same length (and 45 is the only number that will work). With a 45-45-90 triangle, the lengths of the legs are easy to determine:
45-45-90
1-1-sqrt2
Where the hypotenuse corresponds to sqrt2.
Now, your hypotenuse is 10.
To figure out what each leg is, divide 10/sqrt2 (because sqrt2/sqrt2 = 1, which is a leg length in the explanation above).
Problem: you can't divide by radicals. So, we'll have to rationalize the denominator:
(10•sqrt2)/(sqrt2•sqrt2)
This can be rewritten:
10sqrt2/sqrt(2•2)
=10sqrt2/sqrt4
=10sqrt2/2
=5sqrt2
Hope this helps!!
Answer: I think is A, D, E
Step-by-step explanation:
Distribute and you will find 6(3)+6(-y)=18+(-6y)=18-6y
y- intercept = (0, 4), x-intercept = (- 2, 0)
to find the intercepts let x = 0 and y = 0 in the equation
x = 0 → y = 0 + 4 =4 ⇒ y-intercept (0, 4)
y = 0 → 2x + 4 = 0 ⇒ x = - 2 ⇒ x- intercept(- 2, 0)
Solution:
<u>Note that:</u>
- 2(Perimeter of smaller triangle) = Perimeter of larger triangle
<u>Using the perimeter of the smaller triangle, solve for x.</u>
- 2(Perimeter of smaller triangle) = Perimeter of larger triangle
- => 2(3.5 + x + h) = 7 + 4 + 2h
- => 7 + 2x + 2h = 7 + 4 + 2h
- => 2x = 4
- => x = 2
The length of x is 2 units.
