Can you help me with this?

Can someone please help me

ss7ja [257]

Answer:

a.) 1/2

b.) 1/8

c.) 5/8

d.) 1/2

Step-by-step explanation:

for A it is asking for probability of 1 and is 1/2 of the circle

for B it is asking for probability of 3 and it is 1/2 of and 1/4 of the circle so 1/8

for C it is asking for probability of the odd numbers and there is tow odd numbers 1 and 3 the probability of 1 is 1/2 and the probability of 3 is 1/8 adding them up will give you 5/8

for d it asks for the probability of at least 2 so therefor 2, 3, and 4 and they are 1/8 + 1/8 + for 1/4 = 1/2

6 0

3 years ago

Solve the inequality t/4 >7<br> And 2c/3 +1>7

Maru [420]

Answer: c > 12

Step-by-step explanation:tep 1 :

c

Simplify —

3

Equation at the end of step 1 :

c

((2 • —) - 1) - 7 > 0

3

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

1 1 • 3

1 = — = —————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2c - (3) 2c - 3

———————— = ——————

3 3

Equation at the end of step 2 :

(2c - 3)

———————— - 7 > 0

3

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

7 7 • 3

7 = — = —————

1 3

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

(2c-3) - (7 • 3) 2c - 24

———————————————— = ———————

3 3

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

2c - 24 = 2 • (c - 12)

Equation at the end of step 4 :

2 • (c - 12)

———————————— > 0

3

Step 5 :

5.1 Multiply both sides by 3

5.2 Divide both sides by 2

Solve Basic Inequality :

5.3 Add 12 to both sides

c > 12

Inequality Plot :

5.4 Inequality plot for

0.667 X - 8.000 > 0

One solution was found :

c > 12

3 0

3 years ago

Instructions: Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Morgarella [4.7K]

Answer:

y = 3x - 13................slope= 3, point= (5,2)

y = 3x + 11.................slope= 3, point= (2,17)

3y = x + 11................slope= 1/3, point= (-5,2)

3y = x - 13................slope= 1/3, point= (19,2)

Step-by-step explanation:

To match each equation to its slope and point, remember that an equation in y = mx + b has slope m. The point must also satisfy or make true the equation when substituted for (x,y).

y=3x-13 has slope 3. The point (2,17) make it false. But (5,2) makes it true.

17 = 3(2) - 13 2 = 3(5) - 13

17 = 6-13 2 = 15 - 13

17 = - 7 False 2 = 2 True

y=3x+11 has slope 3. This means (2,17) must be true.

3y=x+11 can be converted to y = 1/3x + 11/3. It has slope 1/3. Test each point.

2= 1/3(19) + 11/3 -2 = 1/3(17) + 11/3 2 = 1/3(-5) + 11/3

2 = 19/3 + 11/3 -2 = 17/3 + 11/3 2 = -5/3 + 11/3

False False 2 = 6/3 True

3y=x-13 can be converted to y = 1/3x - 13/3. It has slope 1/3. Test each remaining point.

2= 1/3(19) - 13/3 -2 = 1/3(17) - 13/3

2 = 19/3 - 13/3 -2 = 17/3 - 13/3

2 = 6/3 -2 = 4/3

True False

7 0

3 years ago

Read 2 more answers

Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil

kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

$V = L^{3}$

Donde:

$L$ - Longitud de la arista, medida en dados.

$V$ - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

$L = \sqrt[3]{V}$

Dado que $V = 125\,dados^{3}$ , encontramos que la altura del cubo de mayor tamaño sería:

$L =\sqrt[3]{125\,dados^{3}}$

$L = 5\,dados$

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

$A = L^{2}$

Donde:

$L$ - Longitud de arista, medida en dados.

$A$ - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de $L$ tal que no supere 125 y de un área entera. Es decir:

$L \leq 125\,dados$

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

$L^{2}< 125\,dados^{2}$

Esto nos lleva a decir que:

$L < 11.180\,dados$

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

$n = (11\,dados)^{2}$