3 years ago

Can you help me with this?

Mathematics

1 answer:

satela [25.4K]3 years ago

8 0

I cant hardly see it ,what's the question?

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What is the equation to a graph with the vertex -1,3 and zeros -4 and -2

Mashutka [201]

Answer:

$f(x)=x^2+6x+8$

Step-by-step explanation:

We are given zeros as x=-4, x=-2

so, we can set up function as

$f(x)=a(x+4)(x+2)$

Vertex is at (-1,3)

It means that graph passes through point (-1,3)

so, we can plug x=-1 and f(x)=3

and then we can solve for 'a'

$3=a(-1+4)(-1+2)$

we get

$a=1$

now, we can plug it back

and we get

$f(x)=1(x+4)(x+2)$

now, we can simplify it

$f(x)=x^2+6x+8$

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3 years ago

What is 17x13 divide by four

fiasKO [112]

Bruh u don’t no this is easy

4 0

3 years ago

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Solve for x. x-17=-57 i need help

seraphim [82]

X - 17 = -57
-17. -17
x = -74

hope this helps xo

7 0

2 years ago

Tap the image to view it please I will give crown and points

wariber [46]

Answer:

3848.45mm

Step-by-step explanation:

Area = $\pi r^{2}$

$35^{2}$ = 1225

1225 * $\pi$ = 3848.45

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2 years ago

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Solve the system by finding the determinants and using Cramer's Rule: 2x - y = 4 3x + y = 1

Ahat [919]

Answer:

(1, - 2)

Step-by-step explanation:

2x - y = 4

3x + y = 1

A = $\left[\begin{array}{cc}2&-1\\3&1\end{array}\right]$ = 2(1) - 3( - 1) =2 + 3 = 5

$A_{x}$ = $\left[\begin{array}{cc}4&-1\\1&1\end{array}\right]$ = 4(1) - 1(- 1) = 4 + 1 = 5

$A_{y}$ = $\left[\begin{array}{cc}2&4\\3&1\end{array}\right]$ = 2(1) - 4(3) = 2 - 12 = - 10

x = $\frac{A_{x} }{A}$ = 1

y = $\frac{A_{y} }{A}$ = - 2

(1, - 2)

5 0

2 years ago