im pretty sure you got it right with 40!!
The goal of all algebra equations is to isolate the variable. In 3 step you should first make sure both variables are on the same side. To do that make sure you use the inverse.
For example:
6a + 9 = 3a + 15
because 3a is positive you're going to want to subtract it.
6a + 6 = 3a + 15
-3a -3a
_______________
3a + 6 = 15
Now it's a 2 step equation and you solve it on from there.
Answer:
-6xy
Step-by-step explanation:
(2x-y)x(x-2y)-(x+2y)X(2x-y)
remove the parentheses
2x^2-4xy+xy-2y^2-(2x^2-xy+4xy-2y^2)
collect terms
2x^2-4xy+xy-2y^2-(2x^2+3xy-2y^2)
remove the parentheses
2x^2-4xy+xy-2y^2-2x^2-3xy+2y^2
remove the opposites, collect the terms to get -6xy
Answer:
D. (25π - 50) sq m
Step-by-step explanation:
Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.
I hope this helped! :D