Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
n
b = ---------
(g+l)
Step-by-step explanation:
We need to isolate b. Starting from (g+l)b=n, we divide both sides by (g+l), obtaining
n
b = ---------
(g+l)
The formula subject to q is 
Explanation:
The given formula is 
We need to determine the formula subject to q.
<u>The formula subject to q:</u>
The formula subject to q can be determined by solving the formula for q.
Let us solve the formula.
Thus, we have;
Subtracting both sides by 5p, we have;
Dividing both sides by 5, we get;
Thus, the formula subject to q is
Answer:
See below, I will let graphing part to yourself.
Step-by-step explanation:
First function: domain: 
, range: ![(-\infty, -2]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-2%5D)
, decreasing
Second function: domain: 
, range: , increasing
Third function: domain: 
, range: 
, increasing
Answer:
1. 4.22
2. 19.415
3. nine and thirty- five
4. Three and four hundred twelve
Step-by-step explanation
