Sally has 15 quarts of milk. One is equal to 1 4 of a gallon. How many gallons of milk does Sally have?

Eddi Din [679]

I believe it is 4. I am not 100% sure

7 0

3 years ago

The regular price of a blanket is seven dollars and 89 my cousin has a coupon for six dollars and 16 are how much will she pay f

seropon [69]

Answer:

$1.73

Step-by-step explanation:

$7.89-$6.16=$1.73

3 0

3 years ago

Heights of young adult women in the United States are approximately Normal with a mean of 64 inches and standard deviation 2.7 i

sweet-ann [11.9K]

Answer:

The proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is

$P( X > 72) =0.0015233$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 64 \ inches$

The standard deviation is $\sigma = 2.7 \ inches$

Generally 6 feet is equivalent to 6 * 12 = 72 inches

Generally the proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is mathematically represented as

$P( X > 72) = P(\frac{X - \mu }{\sigma } > \frac{72 - 64 }{ 2.7 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P( X > 72) = P(Z > 2.963 )$

From the z-table

The area under the normal curve to the right corresponding to 2.963 is

$P(Z > 2.963 ) = 0.0015233$

=> $P( X > 72) =0.0015233$

3 0

3 years ago

I need help! ill give brainliest!

Lelu [443]

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$area = DC \times EG$

$area = 27 \times 16$

$area = 432$

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5 0

3 years ago

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

3 years ago