Question

A pile of sand has been stored in the shape of a cone. Mr. Terwilliker knows that the pile is 20 feet tall and 102 feet in circumference at the base. What is the area of the conical tarpaulin needed to cover the pile?

Answer 1

Answer:

The area of tarpaulin is 1315.63 ft^2.  

Step-by-step explanation:

height, h = 20 feet

circumference, C = 102 feet

Let the radius is r.

Circumference, C = 2 x 3.14 x r = 102

r = 16.24 feet

Let the slant height is L.

$L = \sqrt{h^2 + r^2}\\\\L = \sqrt{20^2 + 16.24^2}\\\\L = 25.8 ft$

The curved surface area is

S = 3.14 x r x L

S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2