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valentina_108 [34]
3 years ago
15

If you pay $20 for 16 candy bars what is the cost for per candy

Mathematics
2 answers:
Effectus [21]3 years ago
6 0
$20 divided by 16 equals 1.25.So the cost per candy is $1.25
Olin [163]3 years ago
5 0
<span>$20/16=$1.25/candy bar 
Candy bars cost $1.25 each </span>
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6 0
3 years ago
Is 0,4,8,12 an arithmetic sequence?
Aneli [31]
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6 0
3 years ago
Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:
ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = \frac{12}{36} =\frac{1}{3}

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = \frac{6}{36} =\frac{1}{6}

c) P(EF)

There is no common element between E and F

P(EF) =0

4 0
3 years ago
Read 2 more answers
Please help me if you can! Thank you (:
AnnyKZ [126]

Answer:

The value of f(2) would be -40.

Step-by-step explanation:

Given function is,

f(x) = 2x^3 - 3x^2 - 18x - 8

Substituting x = 2 in the above function,

We get,

f(2) = 2(2)^3 - 3(2)^2 - 18(2) - 8

=2(8) - 3(4) - 36 - 8

=16 - 12 - 44

\implies f(2)= -40

Hence, the value of f(2) would be -40.

4 0
3 years ago
→
Juli2301 [7.4K]
Answer 5.1
Order them from least to greatest and find the middle number. Or by calculating the mean by adding together the middle values and dividing them by two.
3 0
2 years ago
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