Lava
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Cause limestone breaks down dirt and stone
Answer : The rms speed of the molecules in a sample of
gas at 300 K will be four times larger than the rms speed of
molecules at the same temperature, and the ratio
constant with increasing temperature.
Explanation :
Formula used for root mean square speed :
![\mu _{rms}=\sqrt{\frac{3RT}{M}}](https://tex.z-dn.net/?f=%5Cmu%20_%7Brms%7D%3D%5Csqrt%7B%5Cfrac%7B3RT%7D%7BM%7D%7D)
where,
= rms speed of the molecule
R = gas constant
T = temperature
M = molar mass of the gas
At constant temperature, the formula becomes,
![\mu _{rms}=\sqrt{\frac{1}{M}}](https://tex.z-dn.net/?f=%5Cmu%20_%7Brms%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7BM%7D%7D)
And the formula for two gases will be,
![\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20_%7BH_2%7D%7D%7B%5Cmu%20_%7BO_2%7D%7D%3D%5Csqrt%7B%5Cfrac%7BM_%7BO_2%7D%7D%7BM_%7BH_2%7D%7D%7D)
Molar mass of
= 32 g/mole
Molar mass of
= 2 g/mole
Now put all the given values in the above formula, we get
![\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20_%7BH_2%7D%7D%7B%5Cmu%20_%7BO_2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B32g%2Fmole%7D%7BM_%7B2g%2Fmole%7D%7D%7D%3D4)
Therefore, the rms speed of the molecules in a sample of
gas at 300 K will be four times larger than the rms speed of
molecules at the same temperature.
And the ratio
constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.
Answer:
The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds.
Answer: Since one molecule of CO2 contains one molecule carbon atoms, therefore, 0.6 molecule of carbon dioxide will contain 0.6 molecule of carbon.
Mass of C in 0.6 molecule of CO2
Explanation
= No. Of molecule × molar mass
= 0.6× 12gm
=7.2gm