4b² + 8b + 3 = 0
4b² + 2b + 6b + 3 = 0
2b(2b + 1) + 3(2b + 1) = 0
(2b + 3)(2b + 1) = 0
b = -1/2 or b = -3/2
Answer:
(24y^3x-20y^5x^2)/(-3y^5x^2)
= y^3x(24-20y^2x))/(-3y^5x^2)
=(24-20y^2x)/(-3y^2x)
=(24/(-3y^2x))-((20y^2x)/(-3y^2x))
=(-8/y^2x)-(-20/3)
=-8/y^2x + 20/3
Answer:
24
Step-by-step explanation:
Step 1: Define
x = 2
y = 4
16x + 2x² - y²
Step 2: Substitute and Evaluate
16(2) + 2(2)² - 4²
32 + 2(4) - 16
16 + 8
24
√4 + √16 = 2 + 4 = 6 <--- rational
√5 + √36 = √5 + 6 <--- irrational
√9 + √24 = 3 + √24 <--- irrational
2 * √4 = 2 * 2 = 4 <--- rational
√49 * √81 = 7 * 9 = 63 <---rational
3√12 = 3√(4 * 3) = (3 * 2)√3 = 6√3 <---irrational
Hope this helps ^-^
