16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3
Answer:
Step-by-step explanation:
(-3/4)x + 9 = (-1/2)x + 8
9 - 8 = (-1/2)x + (3/4)x
1 = (1/4)x
x = 4
y = (-3/4)4 + 9
y = -3 + 9
y = 6
Answer:
Maintaining a balanced budget ensures monthly obligations are met, with room for savings.With stable cash flow,monthly surpluses can be reserved in an emergency,xontingency fund, standing ready to bail you out of times of financial distress
Answer:
∠ ABC ≈ 137.9°
Step-by-step explanation:
Using the Cosine rule in Δ ABC
cos B = 
with a = 89, b = 144, c = 65
cos B = 
= 
= 
, thus
B = 
( - 
) ≈ 137.9° ( to the nearest tenth )
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
