3 years ago

The probability of A is 7/20, the probability of A intersection B is 49/400 what is the probability of B?

Mathematics

1 answer:

tino4ka555 [31]3 years ago

5 0

Answer:

n(A)+n(B)-49/400=n(AUB)

n(B)=1-7/20+49/400

n(B)=(400+49-140)/400

n(B)=309/400

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