The probability of A is 7/20, the probability of A intersection B is 49/400 what is the probability of B?
1 answer:
Answer:
n(A)+n(B)-49/400=n(AUB)
n(B)=1-7/20+49/400
n(B)=(400+49-140)/400
n(B)=309/400
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The answer would be A) X=5
A round trip is twice the distance herein;
So, (280*2) feet
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Y=2/2x+0
hope this helps
ps~~u dont need that 0
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