If markup is 60% of the cost, you have
... markup = 0.60×cost
... markup/0.60 = cost
... $207.20/0.60 = cost = $345.33
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If markup is 60% of the selling price, the other 40% is the cost. So, the cost is 40/60 = 2/3 of the markup.
... cost = (2/3)×markup = (2/3)×$207.20
... cost = $138.13
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Markup can be specified in terms of either selling price or cost. Those are the usual reference values; there could be others. When only the percentage is given, you don't have enough information to work the problem. You need to know what it is a percentage of. (Example problems in your text may tell you the expected interpretation.)
Hey there!
Here's your answer: m<BDC=69
Here's how I got it:<ADC=112; <ADB and <BDC together form <ABD.
you would add 6x+7and 12x-3 together to equal 112; 18x+4=112, and solve for x
next substitute 6 for x, into m<BDC=12x-3, and simplify!
Hope this helps!
Step-by-step explanation:
Supplementary angle adds up yo 180°
So angle 2 is supplementary to angle 3
Answer:
Apply the distributive property
2x+2(4)=2x+8
Multiply 2 by 4
2x+8=2x+8
Move all terms containing x to the left and subtract 2x
2x+8-2x=8
Combine the opposite terms
2x+8-2x
Subtract 2x from 2x
0+8=8
8=8
All real number
Step-by-step explanation:
Answer:
All except one interval [-2,8]
Step-by-step explanation:
Notice that the function, wich an hyperbola, has a vertical asymptote in both -2 and 8 and there is nothing between this two values.
So we will exclude what's between them out of the domain.
