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Elena L [17]
3 years ago
14

The ages of members of a bowling league are normally distributed with a mean of 43 years and a standard deviation of 4 years.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

35  is  2 standard deviations BELOW the mean of 43

51  is  2 standard deviations ABOVE the mean of 43

 

find z - score for + 2 S.D.     then subtract the z-score for  - 2 S.D.    

 

  This is the percentage ( in decimal form)    of 200 members between the ages of 35 and 51        Can you finish?

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