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4 years ago

Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work

Mathematics

2 answers:

kherson [118]4 years ago

8 0

<h2>Hello!</h2>

The answers is:

The three points that are solution for the equation are:

$(5,0)\\(0,-2)\\(6,0.4)$

To find 3 pairs (x,y) or points that are solutions for the equation, we could find where the function intercepts the x-axis and y-axis, we must remember that the domain of a line is all the real numbers, so by using any input, we will find a solution, which means finding a point that belongs to the line.

So,

Finding the axis intercepts of the line, we have:

x-axis intercept:

Making "y" equal to 0, we have:

$2x-5y=10$

$2x-5*(0)=10$

$2x=10$

$x=\frac{10}{2}=5$

We have that the interception point with the x-axis is (5,0)

y-axis intercept:

Making "x" equal to 0, we have:

$2x-5y=10$

$2*(0)-5y=10$

$0-5y=10$

$5y=-10$

$y=\frac{-10}{5}=-2$

We have that the interception point with the y-axis is (0,-2)

As we know, the domain of a line is equal to the real numbers, Now, we have that any between the points (5,0) and (0,-2) will belong to the line, so, let's try with a point wich x-coordinate (input) is equal to 6 and then find the y-coordinate (output) if the point satisfies the equality, it belongs to the equation to the line.

Substituting x equal to 6, we have:

$2*(6)-5y=10$

$12-5y=10$

$12-10=5y$

$y=\frac{12-10}{5}=\frac{2}{5}$

So, the obtained point is:

$(6,\frac{2}{5})$

$(6,0.4)$

Now, let's prove that it belongs to the equation of the line by substituting it into the equation:

$2*(6)-5*\frac{2}{5}=10$

$12-2=10$

$10=10$

We can see that the equality is satisfied, it means that the point belongs to the line.

Hence, the three points that are solutions for the equation are:

$(5,0)\\(0,-2)\\(6,0.4)$

Have a nice day!

Alla [95]4 years ago

5 0

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is $2x-5y=10$ .

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As $2x-5y=10$ is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into $2x-5y=10$ , we get:

$2(0)-5y=10$

$0-5y=10$

$-5y=10$

$y=\frac{10}{-5}$

$y=-2$

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

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