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lana66690 [7]
3 years ago
13

Jane gets paid $120 for 8 hours. How much does she get paid an hour?​

Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

$15 an hour

Step-by-step explanation:

To find this, we divide 120 by 8.

120 ÷ 8 = 15

So Jane gets $15 an hour

I hope this helped, please mark Brainliest, thank you!

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An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn
elixir [45]
  • The first four terms are : 15000, 14850, 14700, 14550
  • a = 15000 ; d = -150
  • The explicit formula is : a_{n} =  - 150n \:  + 15150

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

a_{n} \:  = nd \: + c

For n = 1

15000 = 1( - 150)  + c

15000 =  - 150 + c

c = 15150

Hence, the explicit formula for the nth term is :

a_{n} \:  =  - 150n \:  + 15150

Learn more : brainly.com/question/12006170

3 0
3 years ago
Which number in the monomial 125x^18 y^3 z^25 need to be changed to make it a perfect cube
Serhud [2]
The power of 25 on the variable z needs to be changed. It has to be divisible by 3.
6 0
3 years ago
The graph below shows the value of Edna's profits f(t), in dollars, after t months:
umka21 [38]
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), x=6 and x=18 are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
x=6
x-6=0
x=18
x-18=0

(x-6)(x-18)=x^{2}-6x-18x+108
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Now that we have our quadratic function, we are going to use the average formula: m= \frac{f(9)-f(3)}{9-3}
where
f(9) is the function evaluated at  the <span>9th month
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m= \frac{f(9)-f(3)}{9-3}
m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}
m= \frac{-27-45}{6}
m= \frac{-72}{6}
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We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>

6 0
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Which of the following inequalities represents a number y that is less than 4 but greater than -1
sukhopar [10]

Four is greater than y, and -1 is less than y

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Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively?
MariettaO [177]
There is no given data table but based on the question, the reaction is
xy <=> x + y
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-----------------------------
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Solve for c using
Kc = c(c) / (M - c)
And the concentration of the xy, x, and y can then be determined
3 0
3 years ago
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