Answer:
Either one of these.
Step-by-step explanation:
volumepile=1/3 (PI r^2)h
but r=h/2, so
volume=1/12 PI h^3
dv/dt=10 ft^3/min
but dv/dt=1/12 PI 3h^2 dh/dt
solve for dh/dt
This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula
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given: r = h/2
V = (1/3)π r^2 h
= (1/3)π (h/2)^2 (h)
= (1/12) π h^3
dV/dt = (1/4)π h^2 dh/dt
for the given data ...
10 = (1/4)π(25)dh/dt
dh/dt = 10(4)/((25π) = 1.6/π feet/min
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
Answer:
She can run 58.5 yards in 9 seconds.
Step-by-step explanation:
39/6=x/9
cross product
6*x=39*9
6x=351
x=351/6
x=58.5
Do I look like a math teacher, I hate math do you hate math?
