10.6666666667 8 divided by 3/4 heh
Step-by-step explanation:

factor it: (start by factoring out the x that is common to all 3 )

next keep factoring the inside...
![= x\left(x^2+x-4x-4\right)\\=x \left[x\left(x+1\right)-4\left(x+1\right)\right]\\=\bold{x\left(x+1\right)\left(x-4\right)}](https://tex.z-dn.net/?f=%3D%20x%5Cleft%28x%5E2%2Bx-4x-4%5Cright%29%5C%5C%3Dx%20%20%5Cleft%5Bx%5Cleft%28x%2B1%5Cright%29-4%5Cleft%28x%2B1%5Cright%29%5Cright%5D%5C%5C%3D%5Cbold%7Bx%5Cleft%28x%2B1%5Cright%29%5Cleft%28x-4%5Cright%29%7D)
So, the only way the function
can be
is if:
- either
, or
, or
<h3>Answer:</h3>
<em>C.</em> 
Answer:
Answer B
Step-by-step explanation:
You have to use the pythagorean theorm which states that a^2+b^2=c^2
So, 7^2+x^2=9^2
49+x^2=81 subtract 49 from both sides of the equation
x^2=32
x=sqrt(32)
sqrt(32)=sqrt(16)*sqrt(2)
=4*sqrt(2)