Help me pleaseee haha
1 answer:
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Answer:
x = 14
y = 4
Explanation:
Ok so, just from looking at the two triangles i can tell they're congruent right triangles. I used different colors to show which sides of the triangle correspond and are equal to each other in my attatched photo.
So the side thats equal to x is the same length as the side that's equal to y+10 on the other triangle.
So we can write the equation x = y + 10.
Using this same method, the side that's equal to x + 2 is the same length as the side that's equal to 4y on the other triangle.
So, we can write the equation 4y = x + 2.
Now we have the equations you could rewrite to be in slope- intercept form so they're easier to graph. But a graphing calculator online would plot it just fine.
If you graph these two equations they'll intersect at the solution ( 14, 4 ). I'll include the graph in my images as well.
To check your answer, you can plug in x and y and see if the triangle sides end up being the same length. I did and it was correct.
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
#SPJ4