You have to divide 4 by 8 which = .5 and then u put the whole # before the decimal which will equal 4.5 , therefore knowing that 5 divided by 8 =0.625 does not help u write the decimal for 4 4/8 but the decimal for 4 4/8 is 4.5
In the figure attached, red circle A and red point B are the circle and external point of interest. Note that we must know where the center of circle A is. If we don't know that, there are construction techniques for finding it, but that is beyond the scope of this answer.
Step 1. Set your compass to a radius greater than half the length of segment AB. Here, we have made the radius AD.
Step 2. Draw arcs above and below the center of segment AB centered at A and B using the radius of Step 1. Here the "arc" is shown a a full (green) circle. Only the points where the arcs intersect (E and F) are of interest, so it is not necessary to draw the full circle.
Step 3. Identify the points of interesection (E and F) of the arcs of Step 2, then draw a line segment between them. This segment (EF) is the perpendicular bisector of AB. Mark point G where it intersects segment AB. As with the green circles, it is not necessary to draw the whole line EF, since we are only interested in the location of the midpoint of AB, which is point G.
Step 4. Using G as the center, and GA or GB as the radius, draw semicircle AHB. The point of intersection H is the only part of that (blue) circle of interest, so it is not necessary to draw the whole thing.
Step 5. Finish the consruction by drawing tangent line BH.
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Answer:
3(n+4) = 12
Step-by-step explanation:
The sum of n and 4 is (n+4). Three times that sum is 3(n+4). When we say it "is 12", we mean it is equal to 12.
3(n +4) = 12
Answer:
Total cost of cementing the path = Rs. 17,000.
Step-by-step explanation:
Let the square garden be PQRS
Let the region inside the garden (PQRS) be KLMN.
<u>Given the following data;</u>
Length of sides of PQRS = 90m
Width of path = 5m
Cost = Rs. 10 per m²
Area of PQRS = 90 * 90
Area of PQRS = 8100m²
<em>To find the area of KLMN;</em>
KL = KN = 90 - (5 + 5)
KL = KN = 90 - 10
KL = KN = 80m
Area of KLMN = KL * KN
Substituting into the equation, we have;
Area of KLMN = 80 * 80
Area of KLMN = 6400 m²
Area of path = Area of PQRS - Area of KLMN
Area of path = 8100 - 6400
Area of path = 1700 m²
Total cost of cementing the path = Area of path * Cost
Total cost of cementing the path = 1700 * 10
<em>Total cost of cementing the path = Rs. 17,000</em>
You'd multiply both by 5, so the answer is 5x+15