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denis23 [38]
3 years ago
5

A company hires some temporary workers. On day one, the temporary employees report they are unable to connect to the network. A

network technician uses a packet analysis tool and finds that many clients are continuously sending out requests for an IP address, but many of them are not receiving a response. Which of the following could be the cause of this issue?
A. Exhausted DHCP scope.
B. Untrusted SSL certificates.
C. Duplicate MAC addresses.
D. Incorrect firewall settings.
Computers and Technology
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

A. Exhausted DHCP scope.

Explanation:

The company has many temporary workers, and permanent workers. There are many people under one network. Since, there are many workers, there can't be untrusted SSL certificates. They all have different devices or computers, so they can't both have duplicate MAC addresses. Lastly, the firewall is supposed to protect against computer viruses and other types of malware, not to harm the user and scope. So, the answer is A.

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Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.

The Code Given:

import java.util.Scanner;

public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
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