All categories

3 years ago

Can someone please help me with this is area of circles

Mathematics

1 answer:

vivado [14]3 years ago

8 0

<h3><u>Given Information :</u></h3>

Radius of the turbine = 32 m
π = 3

<h3 /><h3><u>To calculate :</u></h3>

Area covered by blade when the turbine makes 1 revolution.

<h3><u>Calculation :</u></h3>

We know that,

$\bigstar \: \boxed{\sf {Area_{(Circle)} = \pi r^2}} \\$

$\sf \longmapsto {Area = \{3 \times (32)^2 \} \: m^2 }$

$\sf \longmapsto {Area = \{3 \times 1024 \} \: m^2 }$

$\longmapsto \sf \red {Area = 3072 \: m^2 }$

Therefore,

Correct option is <u>option 4th.</u>

You might be interested in

A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choos

ss7ja [257]

<h3>Hello there i hope you are having a good day :) Your question : A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choose another letter A. What is the probability that both letters are A’s? Write your answer as a percent, with the percent symbol. If needed, round to the nearest tenth. </h3><h3>Firstly the word is SUMMER VACATION there are 14 letters in this word and 2 of them with the letter A So this would be 2/14 and 1/7 Then there is 13 letters because we used one already so it would be 1/13 Then the second A would equal 1/13 and this would be 1/7 and 1/13 you would times both given 1/91 now written that in percent with a percent symbol 1.0989011% So this would be 1.91%</h3><h3>Hopefully that helps you ❤</h3>

7 0

3 years ago

The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad

Leya [2.2K]

<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. $Q_1$ = 14

Median or second quartile i.e. $Q_2$ = 18

Third quartile or upper quartile i.e. $Q_3$ =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. $Q_1$ = 26

Median or second quartile i.e. $Q_2$ = 30

Third quartile or upper quartile i.e. $Q_3$ = 34

and maximum value = 38

The overlap of the two sets of data is as follows.

The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
And the maximum value of seventh grade is same as the lower quartile of eighth grade.

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. $Q_3-Q_1$

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

$8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5$

Hence, the number is : 1.5

6 0

3 years ago

Please help Ill give brainy pleas help please -

mars1129 [50]

The answer to this is a=3

4 0

2 years ago

Round 0.888889 to the nearest hundredth

yKpoI14uk [10]

0.89
.................................................................................................................

4 0

3 years ago

the formula for f= 9/5c + 35 gives the Fahrenheit temperature for Celsius temperature of C degrees. Gwen measured a Celsius temp

kondor19780726 [428]

I think it's 98 I'm sry if it's wrong

6 0

3 years ago