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ki77a [65]
3 years ago
5

Find the value of each trigonometric ratio.A. 37/35B. 12/37C. 12/35D. 37/12​

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

C. 12/35

Step-by-step explanation:

i just guess

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Please help is it greater than or less than<br>7*3_9*2​
mezya [45]
The answer is >,, 21>18
6 0
3 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
2. Give the degree of x2 - 17x + 2x - 5.00
Evgen [1.6K]

Answer:

2

Step-by-step explanation:

Degree is the highest power of a term

I hope im right!

5 0
3 years ago
Read 2 more answers
A total of 35 pints of blood were collected at a local blood drive how many quarts of blood were collected
Step2247 [10]
There was a total of 17.5 quarts of blood that was collected.


Hope this helps! :-)
7 0
3 years ago
A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent
Yuri [45]

the yearly increase of x% assumes is compounding yearly, so let's use that.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\£95000\\ P=\textit{original amount deposited}\dotfill &\£80000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}

95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r

4 0
2 years ago
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