Find the value of each trigonometric ratio.A. 37/35B. 12/37C. 12/35D. 37/12
1 answer:
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Answer:
5.21 m/s²
Step-by-step explanation:
Data provided in the question:
Mass of the hanging object = 4.2 kg
Angle made by the rope with vertical = 28°
Acceleration of gravity = 9.8 m/s²
Now,
let the tension in the rope be 'T'
Thus,
The vertical component of the tension = Tcos(28°)
The horizontal component of the tension = Tsin(28°)
Thus,
For the equilibrium
Net force in vertical direction
Tcos (28) = mg [as Fynet = 0] ..............(1)
and,
Net Horizontal force
Tsin(28°) = ma [as the acceleration of the boxcar is what is causing the object to make the angle] ....................(2)
Now, 2 divided by 1
tan(28°) =
a = g[tan(28°)]
or
a = 9.8 × tan(28°)
or
a = 5.21 m/s²