X = larger number, y = smaller number
x + y = 38...because the sum of the numbers is 38
x = 2y - 10....larger one is 10 less then twice the smaller
now we will sub in 2y - 10 for x back into the first equation
x + y = 38
2y - 10 + y = 38
3y - 10 = 38...add 10 to both sides
3y = 38 + 10
3y = 48 ...divide both sides by 3
y = 48/3
y = 16
now sub 16 in for y back into either of the original equations and find x
x = 2y - 10
x = 2(16) - 10
x = 32 - 10
x = 22
so ur numbers are 16 and 22
Question 4, C, $74.18
Question 5 , also C, $153.90
Hope this helps.
The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
Read more about nonnegative real numbers
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