(1/4ab)^-2
Remove negative exponent by rewritten the equation as (4ab)^2
AUse Product rule to get:
4^2a^2b^2
Now raise 4 to the second power to get:
16a^2b^2
The last answer is correct.
49^2 or 7 I just know from 6th grade
Answer:
Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
Hope this helped :3
-Jazzy <3
Answer:
Given,
P = ₹5,000
R = 5%
T = 6 months
= 1/2 years
S.I = P×R×T/100
= 5,000 × 5 / 2×100
= 250 / 2
= ₹125
Step-by-step explanation:
