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AVprozaik [17]
3 years ago
7

What is the difference in average speed between two cars, one that traveled 160 kilometers in 5 hours, and the other that travel

ed 140 kilometers in the same time? Record and bubble your answer below.
Mathematics
2 answers:
liberstina [14]3 years ago
6 0

Answer:

4

Step-by-step explanation:

KonstantinChe [14]3 years ago
3 0

Answer:

The difference in average speed between two cars, one that traveled 160 kilometers in 5 hours, and the other that traveled 140 kilometers in the same time is:

2 km/h.

Step-by-step explanation:

a) Data and Calculations:

Let A = first car and B = second car

Distance traveled by first car = 160 kilometers (km)

Distance traveled by second car = 140 kilometers

Time taken by each car = 5 hours

Speed of A = 160/5 = 32 km/h

Speed of B = 150/5 = 30 km/h

Difference in speed =  2 km/h (32 - 30)

b) The average speed of a car is given by the distance traveled divided by the time taken to travel the distance.  The speed here is expressed in kilometers per hour (km/h).  It can also be expressed in meters per hour or second, etc.

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What is the result when the number 4 is decreased by 25%?
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Read 2 more answers
How much further up the wall does the ladder in figure 2 reach than
ASHA 777 [7]

The ladder in figure 2 reaches 3.2 feet further up than the ladder in figure 1.

Step-by-step explanation:

Step 1:

In both the given figures, the ladder, the wall and the floor form a right-angled triangle. The floor is the adjacent side, the wall is the opposite side and the ladder is the hypotenuse.

According to the Pythagorean theorem,

a^{2}+b^{2}=c^{2}, where c is the length of the hypotenuse while a and b are the lengths of the other two sides.

Step 2:

For the ladder in figure 1, assume the distance from the floor to the ladder's top is x feet. So a = x, b = 8 and c = 10 (hypotenuse).

a^{2}+b^{2}=c^{2}, x^{2}+8^{2}=10^{2}, x^{2}=100-64=36, x=\sqrt{36}=6 \text { feet }.

So the distance between the floor and the ladder's top is 6 feet.

Step 3:

For the ladder in figure 2, assume the distance between the floor and the ladder's top is y feet. So a = y, b = 4 and c = 10 (hypotenuse).

a^{2}+b^{2}=c^{2}, y^{2}+4^{2}=10^{2}, y^{2}=100-16=48, x=\sqrt{84}=9.1651 \text { feet }.

So the distance between the floor and the ladder's top is 9.1651 feet.

Step 4:

The difference in heights = The wall height in figure 2 - the wall height in figure 1.

The difference in heights = 9.1651 feet - 6 feet = 3.1651 feet.

Rounding this off to the nearest tenth of a foot, we get 3.2 feet.

4 0
3 years ago
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