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3 years ago

What is the area of the trapezoid? [A = 5(61 + b2)h]

Mathematics

1 answer:

Harman [31]3 years ago

7 0

Answer:

A = 105 cm²

Step-by-step explanation:

The area (A) of the trapezoid is calculated as

A = $\frac{1}{2}$ [ (b₁ + b₂)h ]

where h is the height and b₁, b₂ the parallel bases

Here h = 5 , b₁ = 24 and b₂ = 18 , then

A = $\frac{1}{2}$ [ (24 + 18)5 ]

= $\frac{1}{2}$ (42 × 5)

= $\frac{1}{2}$ × 210

= 105 cm²

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