Question

What is the area of the trapezoid? [A = 5(61 + b2)h]

Answer 1

Answer:

A = 105 cm²

Step-by-step explanation:

The area (A) of the trapezoid is calculated as

A = $\frac{1}{2}$ [ (b₁ + b₂)h ]

where h is the height and b₁, b₂ the parallel bases

Here h = 5 , b₁ = 24 and b₂ = 18 , then

A = $\frac{1}{2}$ [ (24 + 18)5 ]

   = $\frac{1}{2}$ (42 × 5)

   = $\frac{1}{2}$ × 210

   = 105 cm²