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3 years ago

What is the area of the trapezoid? [A = 5(61 + b2)h]

Mathematics

1 answer:

Harman [31]3 years ago

7 0

Answer:

A = 105 cm²

Step-by-step explanation:

The area (A) of the trapezoid is calculated as

A = $\frac{1}{2}$ [ (b₁ + b₂)h ]

where h is the height and b₁, b₂ the parallel bases

Here h = 5 , b₁ = 24 and b₂ = 18 , then

A = $\frac{1}{2}$ [ (24 + 18)5 ]

= $\frac{1}{2}$ (42 × 5)

= $\frac{1}{2}$ × 210

= 105 cm²

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Step-by-step explanation:

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Step-by-step explanation:

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kicyunya [14]

Answer: Second option.

Step-by-step explanation:

Given the folllowing Linear Equation:

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You need to substitute the coordinates of each point given in the options into the equation and then evaluate.

1) Substituting $(2, -\frac{1}{7})$ into the equation, you get:

$7(-\frac{1}{7})+2=3(2)-5\\\\-1+2=6-5\\\\1=1\ (TRUE)$

2) Substituting the point $(3, -\frac{3}{7})$ . you get:

$7(-\frac{3}{7})+2=3(3)-5\\\\-3+2=9-5\\\\-1=4\ (FALSE)$

3) Apply the same procedure using the point $(1, -\frac{4}{7})$ :

$7(-\frac{4}{7})+2=3(1)-5\\\\-4+2=3-5\\\\-2=-2\ (TRUE)$

4) Apply the same procedure using the point $(-1, -\frac{10}{7})$

$7(-\frac{10}{7})+2=3(-1)-5\\\\-10+2=-3-5\\\\-8=-8\ (TRUE)$

5) Substituting $(0,-1)$ into the equation:

$7(-1)+2=3(0)-5\\\\-7+2=-0-5\\\\-5=-5\ (TRUE)$

Therefore, the point $(3, -\frac{3}{7})$ is not on the given line.

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