⚠️ Urgent PLS HELP links will be reported Find the value of x .

Thirty students are eating lunch at 5 tables. Each table has the same number of students. How many students are sitting at each

kaheart [24]

30 ÷ 5
6 students at each table

Hope this helps!

5 0

3 years ago

Read 2 more answers

Solve. 7/9 = b/b - 10

kifflom [539]

Answer:

No Solution

Step-by-step explanation:

There are no values of b

that make the equation true.

No solution

8 0

3 years ago

Someone plz help me plz

sukhopar [10]

Answer:

38.5

Step-by-step explanation:

First do 77/2 then you get 38.5, if anything is wrong please tell me!!

4 0

3 years ago

1. Solve proportion 12/15 = 18/b

omeli [17]

We solve the as follows:

1. Solve proportion 12/15 = 18/b
( 12/15 = 18/b ) b
( 12b/15 = 18 ) 15/12
b = 18(15/12)
b = 45/2

2. Solve equations

A. -x + 4 = x +6
-x + 4 - x = x +6 - x
-2x + 4 - 4 = 6 - 4
-2x = 2
x = -1

B. 5n + 7 =7(n+1) -2n
5n + 7 = 7n + 7 - 2n
5n -7n + 2n = 7 - 7
0 = 0

C. -4(p+2) + 8 = 2(p-1) - 7p + 15
-4p - 8 + 8 = 2p - 2 - 7p + 15
-4p + 7p - 2p = -2 + 15 + 8 - 8
p =13

3. Solve a/b x - c = 0 for x
a/b x - c = 0
( a/b x = c ) b/a
x = bc / a

3 0

3 years ago

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li

Fittoniya [83]

Answer:

(a)

$r\geq 5$

$r+y\leq 15$

$8r+12y\geq 120$

$y\geq 0$

(c)Maximum number of hours Lia can work at the restaurant and still meet her earnings goal = 15 hours

(d)Maximum Earning = $160

Step-by-step explanation:

Let r be the number of hours worked at the restaurant.

Let y be the number of hours of yard work,

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour.

$r\geq 5$

Since she does yard work, $y\geq 0$

Lia’s parents allow her to work a maximum of 15 hours per week overall.

$r+y\leq 15$

Lia’s goal is to earn at least $120 per week.

The restaurant, r pays $8 per hour

Yard work, y pays $12 per hour.

Therefore:

$8r+12y\geq 120$

The system of inequalities that represent this problem is therefore:

$r\geq 5$

$r+y\leq 15$

$8r+12y\geq 120$

$y\geq 0$

(b)The graph of the inequality is attached below

(c)When the graph is plotted, the vertices of the feasible region are:

(5,10)
(5, 6.7)
(15,0)

Where the first term is for the number of hours worked in the restaurant.

The maximum value of r possible is 15 from the three points.

Therefore, she can work at the restaurant for 15 hours and still meet her earning goal.

(d)Maximum Amount Lia can earn in 1 Week

At (5,10), Earning=(5X8)+(10X12)=40+120=$160

At (5, 6.7), Earning=(5X8)+(6.7X12)=40+80.4=$120.4
At (15,0) Earning=(15X8)+(0X12)=$120

Since she has to work at least 5 hours at the restaurant, the maximum amount possible is $160.

8 0

3 years ago