Answer: Its 9 i took he test i hope this helps
Step-by-step explanation:
Answer:2
Step-by-step explanation:
Answer:
B) approximately normal with mean 2.3 and standard deviation 2
Step-by-step explanation:
Given the following :
Mean crimes per day = 2.3
Standard deviation = 2
Number of samples = 100
Sampling distribution of the mean:
According to the central limit theorem:
Sample mean = population mean
2.3 = 2.3
The standard deviation of the sample (s) : ratio of the population standard deviation and square root of the sample size.
s = population standard deviation / √sample size
s = 2 / √100
s = 2 / 10
s = 0.2
The central limit theorem also posits that once ths sample size is large enough, the sampling of the sample mean will be approximately normal.
Hence, the distribution is approximately normal, with mean of 2.3 and standard deviation of 0.2
I think the answer should be 6,I just added the two fractions
Answer:
Step-by-step explanation:
a² - b² = (a+ b)(a - b)
1) (2n-4/2n) ÷ (n^2-4/n)

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m
]

Hint : m² - 7m - 8
sum = -7
Product = -8
Factor = (-8), 1
m² - 7m - 8 =m² - 8m + m - 8
= m*(m - 8) + (m-8)
= (m - 8)(m +1)