In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.

8 0

2 years ago

it costs $20 for 4 play tickets and $35 for 7 play tickets. Is cost per ticket constant? why or why not?

KonstantinChe [14]

Answer:

The cost per ticket is constant.

Step-by-step explanation:

Given:

It costs $20 for 4 play tickets and $35 for 7 play tickets.

Now, to get whether cost per ticket is constant or not.

So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.

Now, we check it:

4 play tickets costs = $20.

1 play tickets costs = $20 ÷ 4 = $5.

So, 7 play tickets costs = $5 × 7 = $35.

Thus, the cost of ticket for play is not changing and it is constant.

So the cost per ticket is constant.

Therefore, the cost per ticket is constant.

4 0

3 years ago