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arlik [135]
3 years ago
12

Questions in picture

Mathematics
1 answer:
zmey [24]3 years ago
7 0

Answer:

z-test

hu=50

Step-by-step explanation:

You might be interested in
Use the order of operations to evaluate the expression below.<br> 15 + 25 = 5 - 48 : 6+4 - 2
GenaCL600 [577]

Answer

Step-by-step explanation:

divide 48:6 first -> 15 + 25 = 5 - 8+4 - 2

then solves the right side of this equation from left to right -> 15 + 25 = -1

add 15 + 25 -> 50 = -1

switch -1 place -> 51 = 0

7 0
3 years ago
Jacob earned $80 babysitting and deposited the money into his savings account.The next week he spent $85 on video games.Use inte
IgorC [24]

Answer:

Here's what I get

Step-by-step explanation:

\begin{array}{cccc}\bf{Week}& \textbf{Earned/Spent} & \textbf{Change} & \textbf{Net Change}\\1 & \text{Earned \$80} & + 80 & + 80\\2 & \text{Spent \$85} & \mathbf{- 85} &\mathbf{-5}\\\end{array}

The net chance in Jacob's savings was +80 in the first week, -85 in the second week, and -5 overall.

3 0
3 years ago
5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:
Damm [24]

The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.

(a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}

(b) When <em>x </em>= 0.6 and q = 0.5 m/s, the speed of the wagon is approximately <u>0.243 m/s</u>.

Reasons:

(a) The distance from the cart to the pulley, <em>r</em> is given by Pythagoras's

theorem as follows;

r = √((3 - 0.6)² + x²) = √(2.4² + x²)

The speed of the wagon = \mathbf{\dfrac{dx}{dt}}

The speed of the rope, q = \mathbf{\dfrac{dr}{dt}}

By chain rule, we have;

\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}

\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}

Therefore;

\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}

\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}

(b) The speed of the wagon when <em>x</em> = 0.6 if q = 0.5 m/s is given as follows;

\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243

The speed of the wagon when <em>x </em>= 0.6 and q = 0.5 m/s, \dfrac{dx}{dt} ≈ <u>0.243 m/s</u>

Learn more here:

brainly.com/question/17081984

4 0
3 years ago
Help, answer one that hasn’t been answered
SVEN [57.7K]

4x + 2x = < y

This is because the opposite sides (which is 4x and 2x) of a triangle add up to the exterior angle (<y).

We have to find X.

As you know:

3x + 4x + 2x = 180

because the angles of a triangle add up to 180.

When we add them:

9x = 180

x =  \frac{180}{9}

The 9 is multiplying with the X. We want X only and not 9 with it. So, when we take 9 to the other side, it becomes divide. As a result, the answer to x is:-

x = 20

Substitute value of x into 4x and 2x to find the exterior angle:-

4x:

4(20) = 80

2x:

2(20) = 40

When we add them we get the answer for angle Y:-

80 + 40 = 120

Therefore, we can conclude that:

< y = 120 \: degrees

8 0
3 years ago
Given z1 and z2 below. Calculate z1/z2 and write your answer in rcistheta form.
andre [41]

Answer:

  (2/9)cis(30°)

Step-by-step explanation:

We can express the two numbers in magnitude∠angle form, then find their ratio.

  |z1| = 3√((-1)² +(√3)²) = 3√4 = 6

  ∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

  z2 = 27∠90°

So, the ratio is ...

  z1/z2 = (6∠120°)/(27∠90°) = (6/27)∠(120°-90°)

  z1/z2 = (2/9)∠30°

8 0
3 years ago
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