A 36-m-wide field is how many yards wide?
1 answer:
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Answer:
(Angle DBE) ∠DBE = 50°
Step-by-step explanation:
It is crucial for us to be able to interpret plane geometry related question in order to solve them efficiently.
From the question given; we have analysed and come up with a diagrammatic expression and mathematical solution that clearly explains the question .
Given that
BC and DF are parallel lines.
B is a point on AD
B is a point on AD
BD=BE
work out angle DBE and give a reason.
The diagram can be seen in the attached image below.
SInce ∠BD = ∠DE
Then triangle BDE is an isosceles triangle. In an isosceles triangle ; two sides are equal in length.
The sum of angles in an isosceles triangle = 180° (sum of angles in a triangle)
So;
∠BDE + ∠BED + ∠DBE = 180° (sum of angles in a triangle)
From the diagram; we will see that ∠ABC = ∠BDE (corresponding angle)
Since ; ∠ABC is not given and which is needed to solve this question.
Let's just assume that ∠ABC is 65° , the main thing is to be able to interpret and understand the concept of the question.
Now;
Since
∠ABC = ∠BDE
∠ABC = 65°
∠BDE = 65°
Again;
∠BDE + ∠BED + ∠DBE = 180° (sum of angles in a triangle)
∠BDE will be aso equal to ∠BED ; this is because since the length of the opposite sides of the isosceles triangle are equal, their angles will also be equal.
Therefore;
65° + 65° + ∠DBE = 180° (sum of angles in a triangle)
130 ° + ∠DBE = 180° (sum of angles in a triangle)
∠DBE = 180° - 130°
∠DBE = 50°
Answer:
<h2>3.6°</h2>Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;
is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°