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2 years ago

Work out the following without a calculator (show working out) please help 144x6^-2

Mathematics

1 answer:

Mashutka [201]2 years ago

5 0

Answer:

$144 \times 6^{-2}\\\\= 144 \times \frac{1}{36}\\\\= \frac{144}{36}\\\\= \frac{12}{3}\\\\= 4$

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kondor19780726 [428]

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2 years ago

How do you write the fraction of 6/6 as a sum of fractions in three different ways

zhenek [66]

Answer:

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Step-by-step explanation:

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2 years ago

What is the area of this irregular shape 28in 7in 20in 30in 25in

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2 years ago

the volume of a triangular prism is 42 cubic centimeters. what is the volume of a similar prism that is twice as large as large

Dmitriy789 [7]

Answer:

The volume of the similar prism is $336\ cm^{3}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of the larger prism

y----> the volume of the smaller prism

$z^{3}=\frac{x}{y}$

In this problem we have

$z=2$ -----> the scale factor

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3 0

2 years ago

Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

2 years ago