It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
Step-by-step explanation:
By the Pythagorean Theorem we know
h^2=x^2+y^2 (where h is the hypotenuse and x and y are sides of a right triangle)
w^2+18^2=30^2
w^2=30^2-18^2
w^2=900-324
w^2=576
w=24 in
Answer:
400(π+2) feet square
Step-by-step explanation:
let x be the diagonal of the cage=40√2 at the same time it is the radius of the circle ( the tiger can go in circle)
but since the cage is part of the circle and not full turn πr²/8
area of the circleπr²+ half area square
(π(40√2)²)/8 +40²/2
3200π/8+1600/2
400π+800
400(π+2) feet square
Answer:
The graphed function is Nonlinear
