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AURORKA [14]
3 years ago
11

Witch one is a function?

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer: A

Step-by-step explanation: I hope I help you if it was wrong I'm sorry

kicyunya [14]3 years ago
5 0
<h3>Answer: Choice D</h3>

This shows a list of points where the x coordinate does not repeat. This means that any given x input leads to exactly one y output.

Something like choice A has x = 6 repeated; showing that x = 6 leads to both y = 11 and y = -9 at the same time. So this is why choice A is not a function. Choice B has x = 1 repeat, so it's not a function either. Choice C has x = 19 repeated, so it's not a function.

As a visual tool, you can use the vertical line test to check each set of points. If you are able to draw a single vertical line through more than one point on the graph, then it is not a function.

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Given that these simultaneous equations
Tatiana [17]

The value of k is(3\sqrt{ 10})/2

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= \sqrt{15-2x^2}...........(eq iii)

Substitute the value of y into eq i

x-(\sqrt{15-2x^2}= k

x- (\sqrt{15} - 2x= k

k= (3\sqrt{ 10})/2

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lubasha [3.4K]

Answer:

54

Step-by-step explanation:

to evaluate substitute b = 18 into 3b

3b = 3 × 18 = 54


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3 years ago
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Leya [2.2K]

Answer:

5/4k^2

Step-by-step explanation:

P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.

We will be using the following property of exponents:

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We have

P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.

Thus, the required product is \dfrac{5}{4k^2}.

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There is no diagram for me to look at i dont know how to answer this if this does not have the diagram thank you very much

Step-by-step explanation:


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Step-by-step explanation:

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