5y=2(-6)-4
5y=-12-4
5y=-16
y=-16/5
hope this helps!
Answer:
10 units and (- 5, - 1 )
Step-by-step explanation:
Calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = C(- 8, - 5) and (x₂, y₂ ) = D(- 2, 3)
d =
=
=
=
= 10
Calculate the midpoint using the midpoint formula
( , )
= , )
= , )
= (- 5, - 1 )
A) The revenue = Price (p) * Quantity sold (x)
From the inequality p = 1, 2, 3 ...18
The revenue as a function of quantity sold = R(x)
But R = p * x = px
And x = -8p + 144.
Hence we have R(x) = p( -8p + 144) = - 8p^2 + 144p where p lies between 1 and 18.
B) If the quantity sold, x, is 88 then 88 = -8p + 144; -8p = 88 - 144. We have that p = 7
Then it follows that revenue = 7 * 88 = 616
C) Since R (x) = - 8p^2 + 144p Then dr/dx = -16x + 144. Then we set dr/dx
= 0. So x = 144/ 16 = 9
Then we use x to calculate p as follows. 9 = -8p + 144. Hence p = 135/8 = 16.875
At maximum revenue we have R(x) = - 8(16.875)^2 + 144(16.875) = -2278.56 + 2345.56 = $66.48
D) From C) The company should charge 16.875.
If R = 520. Then 520 = -8p^2 + 144p
So -8p^2 + 144p - 520 = 0
From the quadratic equation our equation becomes x1 = 13 and x2 = 5. We simply substitute
-8(13)^2 + 144(13) - 520 = 0. Hence our answer is 13
The prisoners could do a pattern that could signal who has already been in the room. So for example, one light off, both lights off, one light on, both lights off. But with left and right lights to make the sequence last as long as possible. Then after that sequence to have the last one be the signal that everyone has been in there. I dunno this is tricky lol