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Pavlova-9 [17]
3 years ago
13

Please help me with this question

Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

  see below

Step-by-step explanation:

The third table shows a relationship of y=2x.

_____

Essentially, you have to see whether the value of y/x is constant for all the values in a table. If it is not, then the relation is not proportional.

  in the first table, -4/-2 ≠ -3/-1

  in the second table, -4/-2 ≠ 3/1

  in the fourth table, -4/-2 ≠ 6/2

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What is the correct answer to this question?<br><br> F/2=5/8
ANTONII [103]

Answer:

F = 1.25

Step-by-step explanation:

All you would have to do is cross multiply, so our equations starts at \frac{F}{2} = \frac{5}{8}. We would now multiply F by 8 and 2 by 5. We now have 8F = 10. We can now divide both sides of the equation by 8 to get F = 1.25.

4 0
3 years ago
What is 2+2? i seriously dont know ;)
Cerrena [4.2K]

Answer:

uhhhhhhhhh i think its 8   yep its 8

Step-by-step explanation:

3 0
2 years ago
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san4es73 [151]

Answer:

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Step-by-step explanation:

3 0
3 years ago
The graph of the equation x + 3y = 6 intersects at the y axis at the point whose coordinates are
svp [43]

Answer:

4. (6,0)

Step-by-step explanation:

Plug the points into the equation.

6+3(0)=6

6+0=6

6=6

5 0
3 years ago
In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second
Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is (x+3).

The 3rd number is a square of the second. So, the third number is (x+3)^2.

Therefore, the first, second and third numbers are x,(x+3),(x+3)^2 respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

x+(x+3)+(x+3)^2=77

Therefore, the required equation is x+(x+3)+(x+3)^2=77.

d. On simplification, we get

x+x+3+x^2+6x+9=77                   [\because (a+b)^2=a^2+2ab+b^2]

x^2+(6x+x+x)+(3+9)=77

x^2+8x+12=77

Subtract 77 from both sides.

x^2+8x+12-77=77-77

x^2+8x-65=0

Therefore, the simplified form of the required equation is x^2+8x-65=0.

6 0
2 years ago
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