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3 years ago

Please help me with this question

Mathematics

1 answer:

Vikki [24]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

The third table shows a relationship of y=2x.

_____

Essentially, you have to see whether the value of y/x is constant for all the values in a table. If it is not, then the relation is not proportional.

in the first table, -4/-2 ≠ -3/-1

in the second table, -4/-2 ≠ 3/1

in the fourth table, -4/-2 ≠ 6/2

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Tpy6a [65]

Answer:

$1862 ÷9=$207(each lot)

$207 ×4=$828

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3 years ago

James drives 585 miles from Raleigh to Cleveland Ohio on Friday and back on Sunday.If the trip takes him 18 hours total how many

creativ13 [48]

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3 years ago

How can you write -1/4x-9 on a graph

Dmitrij [34]

Answer:

Slope : -1/4

y-intercept : -9

x... 0 , 1

y... -9 , -37/4

Step-by-step explanation: Graph the line using the slope and y-intercept, or two points. GRAPH IS DOWN BELOW!

Hope this helps you out.

4 0

3 years ago

Thea has a key on her calculator marked $\textcolor{blue}{\bf\circledast}$. If an integer is displayed, pressing the $\textcolor

worty [1.4K]

Answer:

$9$

Step-by-step explanation:

Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.

To find: number that Thea originally entered

Solution:

The final number is $243$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $243$ must be $324$.

As previously the number was squared, so the number before $324$ must be $18$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

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As previously the number was squared, so the number before $81$ must be $9$.

3 0

3 years ago

PLEASE HELP ME!!!!!!!!!

vitfil [10]

$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

8 0

1 year ago